comparing two arrays or strings in bash

[new2unix]

Hi there,
im having issue with comparing two variables, in a bash script.
im trying to do the following:
- get a word from user 1
- split the word into array
- get a character from user2

trying to compare the character entered by user 2 with every single character in the array entered by user1. here is the code:
#######################################
echo "$name1 Enter a word: "
read word
wordarray=(`echo $word | sed 's/./& /g'`) # i used sed to convert it to
# array
echo "$name2 enter a character: "
read guess
guessarray'('echo $guess | sed 's/./&/g'`) # convert the user2 entry to character
#####################################
and then from here, im having trouble finding a way to compare the entry of user2 with every single item in the array entered by user1.

Thanks in advance.

[new2unix]

Hi everybody,
im writing a bash script, and receiving entry from a user, and i need to check if the word has any wildcards in.
do u have any ideas please .

thanks .

[nick.stumpos]

use a backslash before the wildcard you are searching for to escape it

[nick.stumpos]

http://www.google.com/search?q=bash+scripting
sorry if that seems rude, but this is the second simple bash scripting question you have in a row

[leigh123linux]

Threads merged ! , Please stick to one thread next time .

[new2unix]

Sorry, for posting more than one at a time.

Sorry i might didnt explain my need well,

echo " enter a word"
read word

i need to write if statement to check if word entered has any wildcards in
and i dont khow how to represent it.

i know how to convert the word entered to array, by the following
wordarray=(`echo $word | sed 's/./& /g'`)
and then i need to check it
if worddarray has any wildcards in .

thanks again.

[Vouters]

Without an array solution::

#!/bin/bash -x
#
typeset j integer
found=0;
echo "Enter a word: "
read word
echo "Enter a character: "
read guess
for i in `echo $word | sed 's/./& /g'`; do
if [ $guess == $i ];
then
found=1
break
fi
done
if [ $found == 0 ];
then
echo "$guess not in $word"
else
echo "$guess in $word"
fi
exit 0

With an array solution:

#!/bin/bash -x
#
typeset j integer
found=0;
echo "Enter a word: "
read word
echo "Enter a character: "
read guess
wordarray=(`echo $word | sed 's/./& /g'`)
j=0
until [ $j == ${#wordarray[@]} ];
do
if [ $guess = ${wordarray[$j]} ];
then
found=1
break
fi
let j+=1
done
if [ $found == 0 ];
then
echo "$guess not in ${wordarray[@]}"
else
echo "$guess in ${wordarray[@]}"
fi
exit 0

[new2unix]

Thanks a lot, ive had some errors, but i was able to fix them.
Thanks, and sorry for posting two thread in row, i wasnt aware of this.