countdown

Erik-joix · #1 8th May 2004, 05:41 AM

Hi guys.
I don't consider myself to be a coder/programmer but i know some about it. I passed a C++ class a while back. Anyway, i wrote this little script some time ago to basically make it easyer for myself to look for certain types of files and delete (shred) them. I put in a little countdown but i want to make it look nicer. Here's how it is right now.

Code:

echo -e "You have entered\n"
echo -e "Directory: " "\033[0;34m$location"; tput sgr0
echo -e "File type: " "\033[0;34m$type\n"; tput sgr0
echo "Preparing search....."
sleep 5
echo -e "Search starts in ""\033[0;31m3"; tput sgr0 "seconds"
sleep 1
echo -e "Remaining: ""\033[0;33m2"; tput sgr0
sleep 1
echo -e "Remaining: ""\033[0;32m1\n"; tput sgr0
sleep 1

find $location -name "*.$type" >$type-list.txt

This creates a new line after every second but i want it to stay one line and just change the number behind "Remaining". How could i do that?

The output looks like this.

You have entered

Directory: /home
File type: mp3

Preparing search.....
Search starts in 3
Remaining: 2
Remaining: 1

theurge · #2 10th May 2004, 03:49 AM

Ok, I found the solution. I had the idea, just not the right syntax with echo:

Code:

#!/bin/bash
#
# Demonstrates using backspace in a shell script
#
# theurge14@yahoo.com  Sun May  9 21:50:22 CDT 2004

totalLoops=20
counter=1

echo Counting to $totalLoops!
echo
echo -n "Count =  "

while (( counter <= totalLoops ))
do
	if (( counter<10 )); then
		echo -n "$counter "
	else
		echo -n "$counter"
	fi

	(( counter++ ))
	sleep 1

	# Backspace twice over the number, see the man page on echo for more info
	echo -n -e \\b\\b
done

echo
echo "Done!"

The above script will do exactly what you are asking to do. Note this line:

Code:

      echo -n -e \\b\\b

There are your two backspaces. Apparently the octal code only works for printable characters.

Have fun!

Erik-joix · #3 10th May 2004, 04:00 AM

Thank you very much theurge!
This works like a champ.
Here is the part of the script that i altered.

Code:

echo -e "You have entered\n"
echo -e "Directory: " "\033[0;34m$location"; tput sgr0
echo -e "File type: " "\033[0;34m$type\n"; tput sgr0
echo "Preparing search....."
sleep 5
echo -e -n "Search starts in:""\033[0;31m 3"; tput sgr0
echo -e -n " seconds"
sleep 1
echo -e -n "\010""\010""\010""\010""\010""\010""\010""\010""\010""\010" "\033[0;33m2"; tput sgr0
echo -e -n " seconds"
sleep 1
echo -e -n "\010""\010""\010""\010""\010""\010""\010""\010""\010""\010" "\033[0;32m1"; tput sgr0
echo -e -n " seconds"
sleep 1

find $location -name "*.$type" >$type-list.txt

theurge · #4 10th May 2004, 04:02 AM

Aha! Looks like the octal does indeed work.

So either "\010" or \\b or "\b" is a backspace.

Cool to know. Thanks!

Erik-joix · #5 10th May 2004, 04:05 AM

Quote:

Originally posted by theurge
Ok, I found the solution. I had the idea, just not the right syntax with echo:

Code:

#!/bin/bash # # Demonstrates using backspace in a shell script # # theurge14@yahoo.com Sun May 9 21:50:22 CDT 2004 totalLoops=20 counter=1 echo Counting to $totalLoops! echo echo -n "Count = " while (( counter <= totalLoops )) do if (( counter<10 )); then echo -n "$counter " else echo -n "$counter" fi (( counter++ )) sleep 1 # Backspace twice over the number, see the man page on echo for more info echo -n -e \\b\\b done echo echo "Done!"

The above script will do exactly what you are asking to do. Note this line:

Code:

echo -n -e \\b\\b

There are your two backspaces. Apparently the octal code only works for printable characters.

Have fun!

When i posted i didn't see this one.
Anyway, i like this way more.
It looks more professional than what i did.
I'll try and implement your solution into my script by some time tomorrow.

Thanks for the help here!

theurge · #6 10th May 2004, 04:07 AM

Yeah it looks like we're playing post-tag here.

Probably replacing all those octals with "\b" would help shorten the script up.

Good luck.

Erik-joix · #7 11th May 2004, 05:26 AM

I implemented your idea into my script and hope that's alright with you.
I also altered it a little bit to fit my "colored text needs" and you're right. It did significantly shorten the script. Thanks again.

Code:

echo -e "You have entered\n"
echo -e "Directory: " "\033[0;34m$location"; tput sgr0
echo -e "File type: " "\033[0;34m$type\n"; tput sgr0
echo -e "Preparing search....."
sleep 3
echo -n "Search starts in:  "

while (( counter >= liftoff ))
do
	if (( counter>3 )); then
		echo -e -n "\033[0;31m$counter"; tput sgr0
	else
		if (( counter>1 )); then
			echo -e -n "\033[0;33m$counter"; tput sgr0
		else
			echo -e -n "\033[0;32m$counter"; tput sgr0
		fi
	fi
	(( counter-- ))
	sleep 1
	echo -n -e \\b
done

find $location -name "*.$type" >$type-list.txt

theurge · #8 11th May 2004, 06:10 AM

Of course I don't mind, don't mention it. On the contrary I'm rather flattered you used my code.

One comment I might add though on what you have now, on the 2nd nested if structure:

Code:

		if (( counter>1 )); then
			echo -e -n "\033[0;33m$counter"; tput sgr0
		else
			echo -e -n "\033[0;32m$counter"; tput sgr0
		fi

Looks like you have two identical echo statements there.

I wrote this in the original code to make up for the extra digit (when I reached ten) when I used the two backspaces.

I see you took the double backspaces out, but I also see you're counting down instead of up. I guess you're not using numbers greater than 10 so it isn't a problem, but then again I haven't run your code myself so I don't really know.

But anyway, I brought this up as you may decide to remove these lines of code as unnecessary and just stick with:

Code:

			echo -e -n "\033[0;33m$counter"; tput sgr0

Thanks for posting this, I enjoy shell scripting.

Erik-joix · #9 11th May 2004, 01:12 PM

Quote:

Originally posted by theurge
[B]

Code:

		if (( counter>1 )); then
			echo -e -n "\033[0;33m$counter"; tput sgr0
		else
			echo -e -n "\033[0;32m$counter"; tput sgr0
		fi

Looks like you have two identical echo statements there.

I'm sure they aren't identical.

theurge · #10 11th May 2004, 10:28 PM

Late night. Sorry. Thanks.

Erik-joix · #11 12th May 2004, 03:40 AM

And there i thought it can't be done any better.
Wrong.

Code:

#!/bin/bash

clear
printf "%s" "The counter is now: "

for (( counter=1; counter<10; counter++ )) ; do
    printf "%d\b" "$counter"
    sleep 1
done

printf "\n"

exit 0

Picomp314 · #12 12th May 2004, 03:41 AM

counter++
word.

theurge · #13 13th May 2004, 12:44 AM

Yes, a for loop works much better in this case.

This is fun though, change one small thing in your code:

Code:

#!/bin/bash

clear
printf "%s" "The counter is now: "

for (( counter=1; counter<13; counter++ )) ; do
    printf "%d\b" "$counter"
    sleep 1
done

printf "\n"

exit 0

And it produces this:

Code:

The counter is now: 1112

Erik-joix · #14 13th May 2004, 01:05 AM

yes, this code is not supposed to count into the 2 digit region.