[SOLVED] If loop in bash with multiple conditions

[cyborg]

In python this would be easy:

if test_var in ["a","b","c"]: print "Yes"

...but is there a way to do the same in bash? Something like:

if [ "$TEST" == "a" || "b" || "c"  ]; then echo "Yes"; fi

...but obviously, that doesn't work, you'd have to do:

if [ "$TEST" == "a" ] || [ "$TEST" == "b" ] || [ "$TEST" == "c" ]; then echo "Yes"; fi

[jpollard]

It is simple:

case "$TEST" in
"a" | "b" | "c") echo "Yes";;
*) echo nope
esac

[cyborg]

Ah, nice. Spot on. Thanks. I miss OO so much when I need to write a script.

[RupertPupkin]

Originally Posted by cyborg

is there a way to do the same in bash? Something like:

if [ "$TEST" == "a" || "b" || "c"  ]; then echo "Yes"; fi

Yes, there is:

if [[ $TEST =~ ^(a|b|c)$ ]]; then echo "Yes"; fi

[cyborg]

Originally Posted by RupertPupkin

Yes, there is:

if [[ $TEST =~ ^(a|b|c)$ ]]; then echo "Yes"; fi

Magic! I thought I'd seen it somewhere before.